x(3+x)-4=x^2+6x+2

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Solution for x(3+x)-4=x^2+6x+2 equation: 



x(3+x)-4=x^2+6x+2

We move all terms to the left:

x(3+x)-4-(x^2+6x+2)=0

We add all the numbers together, and all the variables

x(x+3)-(x^2+6x+2)-4=0

We multiply parentheses

x^2+3x-(x^2+6x+2)-4=0

We get rid of parentheses

x^2-x^2+3x-6x-2-4=0

We add all the numbers together, and all the variables

-3x-6=0

We move all terms containing x to the left, all other terms to the right

-3x=6

x=6/-3

x=-2

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